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A shower of protons from outer space deposits equal charges +q on the earth and the moon when electrostatic repulsion exactly counterbalances the gravitational attraction. How large is q?

a) \(\begin{array}{l}\sqrt{\frac{4\pi \varepsilon _{0}G}{M_{e}M_{m}}}\end{array} \) b) \(\begin{array}{l}\sqrt{\frac{GMm}{k}}\end{array} \) c) \(\begin{array}{l}\sqrt{\frac{GM_{e}M_{m}}{4\pi \epsilon _{0}}}\end{array} \) d) \(\begin{array}{l}\sqrt{\frac{M_{e}M_{m}}{4\pi \epsilon _{0}G}}\end{array} \) Answer: b) \(\begin{array}{l}\sqrt{\frac{GMm}{k}}\end{array} \) Solution: Gravitational Attraction F=... View Article

A car, starting from rest, has a constant acceleration a1 for a time interval t1 during which it covers a distance s1 . In the next time interval t2, the car has a constant retardation a2 and comes to rest after covering a distance s2 in time t2. Which of the following is correct?

a) \(\begin{array}{l}\frac{a_{1}}{a_{2}}=\frac{s_{1}}{s_{2}}=\frac{t_{1}}{t_{2}}\end{array} \) b) \(\begin{array}{l}\frac{a_{1}}{a_{2}}=\frac{s_{2}}{s_{1}}=\frac{t_{1}}{t_{2}}\end{array} \) c) \(\begin{array}{l}\frac{a_{1}}{a_{2}}=\frac{s_{1}}{s_{2}}=\frac{t_{2}}{t_{2}}\end{array} \) d) \(\begin{array}{l}\frac{a_{1}}{a_{2}}=\frac{s_{2}}{s_{1}}=\frac{t_{2}}{t_{1}}\end{array} \) Solution: d) \(\begin{array}{l}\frac{a_{1}}{a_{2}}=\frac{s_{2}}{s_{1}}=\frac{t_{2}}{t_{1}}\end{array} \)

A horizontal wax bar B rests between a wedge and a vertical wall as shown in the figure. The wedge starts moving towards the wall with a constant acceleration 0.5mm/s^2. The moment the wedge starts moving, a continuous supply of heat from the wall starts melting 1.0mm length of the wax bar per second. If the bar always remains horizontal, which of the following conclusions can you make?

a)The bar first moves downwards and then upwards. b) The bar stops for a moment after 2.0 s from the... View Article

A positive charge is passing through an electromagnetic field in which vec{E} and vec{B} are directed towards the y−axis & z−axis respectively. If a charge particle passes through the region undeviated, then its velocity is/are represented by (here a, b & c are constant).

a) \(\begin{array}{l}\vec{v}=\frac{E}{B}\hat{i}+a\hat{j}\end{array} \) b) \(\begin{array}{l}\vec{v}=\frac{E}{B}\hat{i}+b\hat{k}\end{array} \) c) \(\begin{array}{l}\vec{v}=\frac{E}{B}\hat{i}+c\hat{i}\end{array} \) d) \(\begin{array}{l}\vec{v}=\frac{E}{B}\hat{i}\end{array} \) Solution: b) \(\begin{array}{l}\vec{v}=\frac{E}{B}\hat{i}+b\hat{k}\end{array} \)

The RMS voltage shown in the waveform is

    Solution: \(\begin{array}{l}\sqrt{\frac{1}{T}\int_{0}^{T}(10)^{2}dt}\end{array} \) \(\begin{array}{l}\sqrt{\frac{1}{T}(10)^{2}Tdt}\end{array} \) \(\begin{array}{l}\sqrt{(10)^{2}dt} = 10V\end{array} \)