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Question

\( NaBH _{4}= \) \( A \frac{ H _{2} 0 / H ^{+}}{4} \rightarrow B \)

A
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B
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C
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D
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Solution

The correct option is D
Sodium borohydride is a mild reducing agent, it will reduces aldehyde and ketones to alcohols, but does not reduce esters, carboxylic acids or amides.
5-hydroxyhexanoic acid
Product A is 5- hydroxyhexanoicacid. It has both alcohol and carboxylic acid group in it. Thus, it undergoes intramolecular esterification in the presence of acid and forms the cyclic ester product.
\( \stackrel{ H ^{+}}{\longrightarrow} \)

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