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B
an equilateral triangle
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C
a scalene triangle
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D
a right triangle
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Solution
The correct option is D a right triangle Let the vertices be A(0,0), B(0,3) and C(3,0). Now the measure of sides are AB=3 units BC=√(0−3)2+(3−0)2=√32+32=3√2units. AC=3 units. Hence, we can observe that AB2+AC2=32+32=2(32)=BC2.
Thus, it follows Pythagoras theorem with BC being the hyptenuse and AC and AB being the perpendicular sides.
Hence, the above vertices form a right angled triangle.