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Question

0.15 g of an organic compound gave 0.12g of AgBr by Carius method. The % of bromine in the Compound is(Molar mass of AgBr=188)
 
  1. 24.08
  2. 34.04
  3. 42.06
  4. 38.96


Solution

The correct option is B 34.04
% of bromine=80× mass of AgBr×100188×0.15=80×0.12×100188×0.15=34.04

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