Question

0.15g of an organic compound gives 0.12g of silver bromide by the Carius method. The percentage of bromine in the compound is :

• A. 42.06
• B. 38.96
• C. 24.08
• D. 34.04

Answer 1

The correct option is D 34.04

%$Br=\frac{80}{188}\times \frac{massofAgBr}{massofcompound}\times 100$
$=\frac{80}{188}\times \frac{0.12}{0.15}\times 100$
$=34.0425$
$Br\approx 34.04$%