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Question
0.2(M) solution of monobasic acid is dissociated to 0.95% calculate its dissociation constant.
C = 0.2 M
0.2(M) solution of monobasic acid is dissociated to 0.95% calculate its dissociation constant.
C = 0.2 M
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Solution
The correct option is B
As the concentration of H+ from acids is 0.2×0.95×10−2=1.9×10−3 M hence H+ from self-ionization of water can be neglected.
Ka=Cα2
=0.2×(0.0095)2
=1.8×10−5
C=0.2 mole/lit
or
0.2 mole lit−1
As the concentration of H+ from acids is 0.2×0.95×10−2=1.9×10−3 M hence H+ from self-ionization of water can be neglected.
Ka=Cα2
=0.2×(0.0095)2
=1.8×10−5
C=0.2 mole/lit
or
0.2 mole lit−1
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