Question

Solve for $f,0.25(4f-3)=0.05(10f-9)$.

Answer 1

Given $0.25(4f-3)=0.05(10f-9)$
$\Rightarrow 1.00\left(f\right)-0.75=0.5f-0.45$
$\Rightarrow f-0.5f=0.75-0.45$
$\Rightarrow 0.5f=0.3$
$\Rightarrow f=\frac{0.3}{0.5}$
$\therefore f=0.6$