$0.44 g$ of a colourless oxide of nitrogen occupies $224 m L$ . at STP. The compound is-

N_{2} O

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N O

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N_{2} O_{5}

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N O_{2}

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Solution

The correct option is A $N_{2} O$
Number of moles of gas at STP $= \frac{224}{22400} = 0.01$

0.01 mole of gas weighs 0.44 gm.

Therefore 1 mole of gas should weigh 44 gm.

Hence, gas is $N_{2} O$ .

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