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Question

1.00g of non-electrolyte solute dissolved in 50 g of benzene lowered the point of benzene by 0.40K. The freezing point depression constant of benzene is 5.12 K kg/mol. Find the molar mass of the solute.

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Solution

As ΔTf=Kf×m

where,
Kf= Freezing point depression constant;
ΔTf= Depression in freezing point;
m= molality

Now,
ΔTf=Kf×W2×1000M2×W1

where,
W2= mass of solute; W1= mass of benzene i.e. solvent; M2= molar mass of solute

0.40=5.12×1.0×1000M2×50

M2=256

Thus, the molar mass of non-electrolyte is 256.

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