CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

12+22+32+42+...+72= .

A
120
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
140
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
105
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 140
The sum of the squares of the first n natural numbers is given by
Sn=12+22+32+...+n2
=n(n+1)(2n+1)6.

Here, n=7.
S7=12+22+32+42+...+72
=7(7+1)(2×7+1)6
=7×8×156
=140
Thus, 12+22+32+42+...+72=140.



flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sum of Squares of First N Natural Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon