1-4 dichlorohexane 1 mole - NaI 1 mole Product of the reaction is -

The correct option is D I CH_2 CH_2 CH_2 Cl|CH CH_2 CH_3 It is a type of SN_2 reaction.So, 1^o Cl is more reaction than 2^o Cl So,it will ...

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Nucleophilic Substitution in Alkyl Halides

1-4 dichloroh...

Question

1-4 dichlorohexane (1 mole) + NaI (1 mole) $A c e t o n e - ---- \to$ Product of the reaction is :

C l - C H_{2} - C H_{2} - C H | I - C H_{2} - C H_{3}

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I - C H_{2} - C H_{2} - C H | C l - C H_{2} - C H_{3}

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H_{2} C = C H - C H_{2} - C H | C l - C H_{2} - C H_{3}

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I - C H_{2} - C H_{2} - C H_{2} - C H | C l - C H_{2} - C H_{3}

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A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

C H_{3} - C H_{2} - \oplus C H_{2}

C H_{3} - C H | F - \oplus C H_{2}

C H_{3} - C H | B r - \oplus C H_{2}

C H_{3} - C H | C l - \oplus C H_{2}

C H_{3} - C H_{2} - C H | C O O H - C H_{2} - C l | C H - C H_{2} - C H_{3}

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