1 5 2 8 + A ––––––––– 1 5 B 0 –––––––––
A =___ and B =___
We know that A is a single digit number which when added to 8 gives a number with 0 in its ones place.
For ones digit, 8+ 2 = 10
⇒ A = 2 and 1 is carried over to the tens place column.
For tens digit, 1(carried over) + 2 = 3 = B
The hundreds and thousands digits remain unchanged.
Hence, A = 2 and B = 3.
1 5 2 8 + 2 ––––––––– 1 5 3 0 –––––––––