1 - 6 - 3 - -4 - 5- - 7 - -27-3-60-17-320

The correct option is B 60Using BODMAS to solve the given expression, 1 + 6 ÷ 3 (4 + 5) × 7 = 1 + 6÷ 3 (9) × 7 = 1 + 2 9 × 7 = 1 + 2 63 = 3 63 = 60 ...

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Byju's Answer

Standard VIII

Mathematics

Division of Integers

1 + 6 ÷ 3 - (...

Question

$1 + 6 \div 3 - (4 + 5) \times 7 =$ ____.

\frac{27}{3}

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- 60

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\frac{- 17}{3}

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20

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Solution

The correct option is B $- 60$
Using BODMAS to solve the given expression,
$1 + 6 \div 3 - (4 + 5) \times 7$
$= 1 + 6 \div 3 - (9) \times 7$
$= 1 + 2 - 9 \times 7$
$= 1 + 2 - 63$
$= 3 - 63$
$= - 60$

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Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$