1. A metal reacts with chlorine and forms two chlorides A and B. A has 77.45% and B has 84.93% of chlorine. Calculate the mass of chlorine that combines with one gram of metal and show that the law of multiple proportions is obeyed.
1. A metal reacts with chlorine and forms two chlorides A and B. A has 77.45% and B has 84.93% of chlorine. Calculate the mass of chlorine that combines with one gram of metal and show that the law of multiple proportions is obeyed.
Dear student!
Let 100 gm of A has = 77. 45 gm Chlorine ,
And, 100 gm of B has = 84.93 gm chlorine
Here weight of chlorine (A) =77.45 gm
Weight of metal = 100-77.45 = 22.55
Similarly weight of chlorine(B) =84.93 gm
Weight of metal = 100-84.93 = 15.07
Hence, 1 gm metal will react with = 84.93 /15.07 = 5.63 gm of chlorine
Hence, in case (A)
22.55 gm of metal combines with 77.45 gm of chlorine
so, 1 gm metal will react with,
= 77.45 / 22.55 = 3.43 gm--.---2
Here,in both the cases A and B the weight of chlorine which combines with fixed amount of metal ( 1 gm) are 3.43gm and 5.63 gm which are in the simple ratio of 5:3
Hence the chlorides follow the law of multiple proportion.
Dear student!
Let 100 gm of A has = 77. 45 gm Chlorine ,
And, 100 gm of B has = 84.93 gm chlorine
Here weight of chlorine (A) =77.45 gm
Weight of metal = 100-77.45 = 22.55
Similarly weight of chlorine(B) =84.93 gm
Weight of metal = 100-84.93 = 15.07
Hence, 1 gm metal will react with = 84.93 /15.07 = 5.63 gm of chlorine
Hence, in case (A)
22.55 gm of metal combines with 77.45 gm of chlorine
so, 1 gm metal will react with,
= 77.45 / 22.55 = 3.43 gm--.---2
Here,in both the cases A and B the weight of chlorine which combines with fixed amount of metal ( 1 gm) are 3.43gm and 5.63 gm which are in the simple ratio of 5:3
Hence the chlorides follow the law of multiple proportion.
