1 kg piece of copper is drawn into a wire 1 mm2 thick, and another 1 kg copper piece into a wire 2 mm2 thick. Compare the resistance of these wires.
The volume of wire = length x Cross-sectional Area.
Since, the volume is same in both the cases, the length of the second wire will be half of the length of 1st wire.
Using R = ρLA, we get the resistance of the 1st wire is 4 times the value of resistance of the 2nd wire.