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Question

$$1\ mol\ H_{2}SO_{4}$$ will exactly neutralise which of the following?


A
2 mol of NH3
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B
1 mol of Ba(OH)2
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C
0.5 mol of Ba(OH)2
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D
2 mol of KOH
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Solution

The correct options are
A $$2\ mol$$ of $$NH_3$$
B $$1\ mol$$ of $$Ba(OH)_{2}$$
D $$2\ mol$$ of $$KOH$$
$$2NH_{3} + H_{2}SO_{4}\rightarrow (NH_{4})_{2}SO_{4}$$
$$Ba(OH)_{2} + H_{2}SO_{4} \rightarrow BaSO_{4} + 2H_{2}O$$
$$2KOH + H_{2}SO_{4} \rightarrow K_{2}SO_{4} + 2H_{2}O$$.

Chemistry

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