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Question

1 mol of HI is converted into H2 and I2 at 400 K. What would be the value of Kp if 23rd of HI is left at equilibrium?
  1. 14
  2. 12
  3. 116
  4. 1


Solution

The correct option is C 116
2HIH2+I2
1            0       0 
23          16      16

Since Δn=0, Kp=Kc
Kp=16×1623×23=116

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