Question

# $$1\ mol$$ of iron $$(Fe)$$ reacts competely with $$0.65\ mol\ O_{2}$$ to give a mixture of only $$FeO$$ and $$Fe_{2}O_{3}$$. Mole ratio ferrous oxide to ferric oxide to ferric oxide is:

A
3:2
B
4:3
C
20:13
D
none of these

Solution

## The correct option is B $$4:3$$$$4:3$$We have,$$Fe+\dfrac{1}{2}O_2\rightarrow FeO$$$$\Rightarrow a+2b=1$$.......(1)$$2Fe+\dfrac{3}{2}O_2\rightarrow Fe_2O_3$$$$\Rightarrow a+3b=1.3$$......(2)solving (1) and (2), we have$$a=0.4,b=0.3$$Therefore the ratio is, $$4:3$$Chemistry

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