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Question

$$1\ mol$$ of iron $$(Fe)$$ reacts competely with $$0.65\ mol\ O_{2}$$ to give a mixture of only $$FeO$$ and $$Fe_{2}O_{3}$$. Mole ratio ferrous oxide to ferric oxide to ferric oxide is:


A
3:2
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B
4:3
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C
20:13
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D
none of these
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Solution

The correct option is B $$4:3$$
$$4:3$$

We have,

$$Fe+\dfrac{1}{2}O_2\rightarrow FeO$$

$$\Rightarrow a+2b=1$$.......(1)

$$2Fe+\dfrac{3}{2}O_2\rightarrow Fe_2O_3$$

$$\Rightarrow a+3b=1.3$$......(2)

solving (1) and (2), we have

$$a=0.4,b=0.3$$

Therefore the ratio is, $$4:3$$


Chemistry

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