Byju's Answer

Standard XII

Chemistry

Catalytic Transfer Hydrogenation

1 mole of N2H...

Question

1 mole of N2H4 lost 10 moles of electrons and formed a new compound,'Y' in which all hydrogens are present with out change in the oxidation state .The oxidation number of nitrogen in the new compound 'Y' is

Open in App

Solution

Suggest Corrections

Similar questions

1

mole of

N_{2} H_{4}

lost

10

moles of electrons and formed a new compound,

Y

, in which all hydrogens are present without any change in the oxidation state. The oxidation number of nitrogen in the new compound,

Y

, is:

Q. A mole of

N_{2} H_{4}

loses 10 mol of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y ? ( There is no change in the oxidation number of hydrogen. )

A mole of $N_{2} H_{4}$ loses 10 mol of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (There is no change in the oxidation number of hydrogen.)

Q. A mole of

N_{2} H_{4}

loses

10

mol of electrons to form a new compound

Y

. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in

Y

? (There is no change in the oxidation number of hydrogen)

O n e m o l e

N_{2} H_{4}

loses

10 m o l e s

of electrons to form a new compound

Y

. Assuming that all nitrogen appear in the new compound, what is the oxidation state of nitrogen in compound

Y

[There is no change in the oxidation state of hydrogen.]

Join BYJU'S Learning Program

Select...