1) The Velocity of a car decreases from 20 m/s to 10 m/s in certain time interval .Find retardation of car if distance covered by car during this time is 300 m.
2) Brakes are applied to train moving at 40 km/h. If the train comes to stop after 1 minute , calculate the retardation and the distance covered by train after brakes are applied.

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Solution

1) Use formula
$v^{2} = u^{2} + 2 a s$
Substitute
v=10,
u=20,and
s=300m

2) 40 km/hr
$= \frac{40000}{3600} = \frac{400}{36}$
$= 11.11 m / s e c$
$t = 60 s e c$
use formula
v=u+at

use v=0,u=11.11

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1) Use formula v2=u2+2as Substitute v=10, u=20,and s=300m 2) 40 km/hr =400003600=40036 =11.11 m/sec t=60 sec use formula v=u+at use v=0,u=11.11

1) Use formula
$v^{2} = u^{2} + 2 a s$
Substitute
v=10,
u=20,and
s=300m

2) 40 km/hr
$= \frac{40000}{3600} = \frac{400}{36}$
$= 11.11 m / s e c$
$t = 60 s e c$
use formula
v=u+at

use v=0,u=11.11