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Question

1) Write the IUPAC names of the following coordination compounds:
A) [Pt(NH3)2Cl(NO2)]

2) Write the IUPAC names of the following coordination compounds:
B) K3[Cr(C2O4)3]

3) Write the IUPAC names of the following coordination compounds:
C) [CoCl2(en)2]Cl

4) Write the IUPAC names of the following coordination compounds:
D) [Co(NH3)5(CO3)]Cl

5) Write the IUPAC names of the following coordination compounds:
E) Hg[Co(SCN)4]

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Solution

A) To write the IUPAC name of coordination compound,

first, we write the name of cation then anion.

Naming of the simple part

When cationic or anionic part are not complex, while writing the name of these parts we do not mention the number of the atoms or ions, we write only simple name.

Ex.

K4[Fe(CN)6]

Potassium hexacyanidoferrate (II)

[Co(NH3)6]Cl3
Hexaamminecobalt(III) chloride

Naming of the complex part

I. When we do the nomenclature of the complex part, first we do the naming of ligand then central metal atom/ion.

II.If more than one type of ligand is present in the complex, then the ligands are named in an alphabetical order.

III. After, naming of ligands, the central metal ion is to be named followed by its oxidation state in Roman numbers in brackets. As per IUPAC, If the complex part is neutral/cationic, then the central metal ion is to be named as it is. If the complex part is anionic, then the name of central metal ion ends with 'ate’ using their latin name.

IUPAC name of the given compound

Let the oxidation state of platinum be x.

So,

x+2(0)+(1)+(1)=0

x=+2

[Pt(NH3)2Cl(NO2)]

DiamminechloridonitritoNplatinum (II)

B) To write the IUPAC name of coordination compound,

first, we write the name of cation then anion.

Naming of the simple part

When cationic or anionic part are not complex, while writing the name of these parts we do not mention the number of the atoms or ions, we write only simple name.

Ex.

K4[Fe(CN)6]

Potassium hexacyanidoferrate (II)

[Co(NH3)6]Cl3
Hexaamminecobalt(III) chloride

Naming of the complex part

I. When we do the nomenclature of the complex part, first we do the naming of ligand then central metal atom/ion.

II.If more than one type of ligand is present in the complex, then the ligands are named in an alphabetical order.

III. After, naming of ligands, the central metal ion is to be named followed by its oxidation state in Roman numbers in brackets. As per IUPAC, If the complex part is neutral/cationic, then the central metal ion is to be named as it is. If the complex part is anionic, then the name of central metal ion ends with 'ate’ using their latin name.

IUPAC name of the given compound

Let the oxidation state of platinum be x.

So,

x+3(+1)+3(2)=0

x=+3

K3[Cr(C2O4)3]

potassium trioxalatochromate (III)

C) To write the IUPAC name of coordination compound,

first, we write the name of cation then anion.

Naming of the simple part

When cationic or anionic part are not complex, while writing the name of these parts we do not mention the number of the atoms or ions, we write only simple name.

Ex.

K4[Fe(CN)6]

Potassium hexacyanidoferrate (II)

[Co(NH3)6]Cl3
Hexaamminecobalt(III) chloride

Naming of the complex part

I. When we do the nomenclature of the complex part, first we do the naming of ligand then central metal atom/ion.

II.If more than one type of ligand is present in the complex, then the ligands are named in an alphabetical order.

III. After, naming of ligands, the central metal ion is to be named followed by its oxidation state in Roman numbers in brackets. As per IUPAC, If the complex part is neutral/cationic, then the central metal ion is to be named as it is. If the complex part is anionic, then the name of central metal ion ends with 'ate’ using their latin name.

IUPAC name of the given compound

Let the oxidation state of platinum be x.

So,

x+2(1)+2(0)+(1)=0

x=+3

[CoCl2(en)2]Cl

Dichloridobis(ethane-1,2-diamine)cobalt(III)chloride

D) To write the IUPAC name of coordination compound,

first, we write the name of cation then anion.

Naming of the simple part

When cationic or anionic part are not complex, while writing the name of these parts we do not mention the number of the atoms or ions, we write only simple name.

Ex.

K4[Fe(CN)6]

Potassium hexacyanidoferrate (II)

[Co(NH3)6]Cl3
Hexaamminecobalt(III) chloride

Naming of the complex part

I. When we do the nomenclature of the complex part, first we do the naming of ligand then central metal atom/ion.

II.If more than one type of ligand is present in the complex, then the ligands are named in an alphabetical order.

III. After, naming of ligands, the central metal ion is to be named followed by its oxidation state in Roman numbers in brackets. As per IUPAC, If the complex part is neutral/cationic, then the central metal ion is to be named as it is. If the complex part is anionic, then the name of central metal ion ends with 'ate’ using their latin name.

IUPAC name of the given compound

Let the oxidation state of platinum be x.

So,

x+5(0)+(2)+(1)=0

x=+3

[Co(NH3)5(CO3)]Cl

Pentaamminecarbonatocobalt(III)chloride

E) To write the IUPAC name of coordination compound,

first, we write the name of cation then anion.

Naming of the simple part

When cationic or anionic part are not complex, while writing the name of these parts we do not mention the number of the atoms or ions, we write only simple name.

Ex.

K4[Fe(CN)6]

Potassium hexacyanidoferrate (II)

[Co(NH3)6]Cl3
Hexaamminecobalt(III) chloride

Naming of the complex part

I. When we do the nomenclature of the complex part, first we do the naming of ligand then central metal atom/ion.

II.If more than one type of ligand is present in the complex, then the ligands are named in an alphabetical order.

III. After, naming of ligands, the central metal ion is to be named followed by its oxidation state in Roman numbers in brackets. As per IUPAC, If the complex part is neutral/cationic, then the central metal ion is to be named as it is. If the complex part is anionic, then the name of central metal ion ends with 'ate’ using their latin name.

IUPAC name of the given compound

Let the oxidation state of platinum be x.

So,

x+(+2)+4(1)=0

x=+2

Hg[Co(SCN)4]

Mercury(II)tetrathiocyanato-S-cobaltate(II)


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