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Question

102 moles of Fe3O4 is treated with excess of KI solution in presence of dilute H2SO4, the products are
Fe2+ and I2 (g). What volume of 0.1 (M) Na2S2O3 will be needed to reduce the liberated I2 (g) ?



A
50 ml
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B
100 ml
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C
200 ml
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D
400 ml
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Solution

The correct option is D 200 ml

Fe3O4+2IFe2++I2
no.of moles of I2 produced =102moles
Let v ml 0.1(M)Na2S2O3 solution is required
v×104=2×102
or v=200 ml.

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