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Question

10 g of carbon is reacted with 100 g of Cl2 to form CCl4. The incorrect statements are:

A
Carbon is the limiting reagent
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B
Chlorine is the excess reagent
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C
108.4 g of CCl4 is formed
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D
0.833 moles of CCl4 are formed
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Solution

The correct option is D 0.833 moles of CCl4 are formed
C+2Cl2CCl4
Moles of carbon =1012=0.833 moles
Moles of chlorine=10071=1.408 moles
Finding the limiting reagent:
C=given moles stoichiometric coefficient=0.8331=0.833Cl2=given molesstoichiometric coefficient=1.4082=0.704
Hence, the limiting reagent will be chlorine.
2 moles of Cl2 produce 1 mole of CCl4
1.408 moles produce 12×1.408=0.704 moles of CCl4
Mass of CCl4 produced=0.704×154=108.42 g

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