$10$ grams each of $O_{2}, N_{2}$ and $C l_{2}$ are kept in three bottles. The correct order of arrangement of bottles containing decreasing number of molecules is:

O_{2} > N_{2} > C l_{2}

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C l_{2} > N_{2} > O_{2}

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C l_{2} > O_{2} > N_{2}

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N_{2} > O_{2} > C l_{2}

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Solution

The correct option is D $N_{2} > O_{2} > C l_{2}$
No. of molecules $= \frac{W e i g h t}{M o l e c u l a r W e i g h t} \times N_{A}$

Molecular weight order is $C l_{2} > O_{2} > N_{2}$ .

Therefore, the order of no. of molecules is $N_{2} > O_{2} > C l_{2}$ .

Hence, option $D$ is correct.

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