CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

10 mL of a strong acid solution of pH = 2.000 is mixed with 990 mL of another strong acid solution of pH = 4.000. What will be the pH of the resulting solution?
log1.99=0.3

A
4.002
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4000
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 3.7
[H+] after mixing 102×10+104×9901000=0.1+0.09901000=0.19901000=1.99×104pH=(log1.99×104)
pH=(4log1.99)
pH=40.3=3.7

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon