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Question

10 mL of a strong acid solution of pH = 2 is mixed with 990 mL of another strong acid solution of pH = 4. The pH of resulting solution will be : 
  1. 4.002
  2. 4
  3. 4.2
  4. 3.7


Solution

The correct option is D 3.7
 
pHsolution1=2  ;  M1=[H+]=102pHsolution2=4  ;  M2=[H+]=104M3=[H+]after mixing V1=10 mL   , V2=990 mLV3=V1+V2=1000 mLApplying:
M1V1+M2V2=M3V3M3=M1V1+M2V2V3=(102× 10)+(104× 990)1000      =0.1+0.09901000=1.99×104pH= log10[1.99×104]pH=3.7 Ans.

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