CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

pH the Power of H

10 mL of a st...

Question

10 mL of a strong acid solution of pH = 2 is mixed with 990 mL of another strong acid solution of pH = 4. The pH of resulting solution will be :

A

4.002

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

4.2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

3.7

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 3.7

$p H_{s o l u t i o n 1} = 2; M_{1} = [H^{+}] = 10^{- 2} p H_{s o l u t i o n 2} = 4; M_{2} = [H^{+}] = 10^{- 4} M_{3} = [H^{+}]_{a f t e r m i x i n g} V_{1} = 10 m L, V_{2} = 990 m L V_{3} = V_{1} + V_{2} = 1000 m L A p p l y i n g :$
$M_{1} V_{1} + M_{2} V_{2} = M_{3} V_{3} M_{3} = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{3}} = \frac{(10^{- 2} \times 10) + (10^{- 4} \times 990)}{1000} = \frac{0.1 + 0.0990}{1000} = 1.99 \times 10^{- 4} p H = - l o g_{10} [1.99 \times 10^{- 4}] p H = 3.7 A n s .$

Suggest Corrections

thumbs-up

0

Similar questions

400 m L

of a strong acid solution of pH = 3 is mixed with

600 m L

of another strong base solution of pOH = 4. The pH of resulting solution will be :
[Given,

log (3.4) = 0.531

]

Join BYJU'S Learning Program

explore_more_icon

Explore more

pH the Power of H

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon