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Standard XII

Chemistry

Empirical & Molecular Formula

10 ml of gase...

Question

10 ml of gaseous hydrocarbon on combustion gives 40 ml of $C O_{2}$ (g) and 50 ml of $H_{2} O$ (vap.). The hydrocarbon is

C₄H₅

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C₈H₁₀

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C₄H₈

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C₄H₁₀

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Solution

The correct option is D
C₄H₁₀

$C_{x} H_{y}$ $O_{2}$ $⟶$ $C O_{2}$ + $H_{2} O$

10ml 40ml 50ml

1mole 4mole 5mole

Apply POAC for C

X =4

Apply POAC for H

Y=10

Suggest Corrections

Similar questions

10

mL of gaseous hydrocarbon on combustion gives

40

mL of

C O_{2} g

and

50

H_{2} O

(vapour). The hydrocarbon is:

Q. At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20%

O_{2}

by volume for complete combustion. After combustion the gases occupy 330 mL. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is:

At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requries 375 mL air containing 20% $O_{2}$ by volume for complete combustion. After combustion the gases occupy 330 mL. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is:

Q. A gaseous hydrocarbon gives upon combustion,

0.72 g

water and

3.08 g

C O_{2}

. The empirical formula of the hydrocarbon is:

Q. 40 ml of hydrocarbon on combustion gave 120 ml

C O_{2}

and 80 ml water vapour.
The molecular formula of hydrocarbon is?

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10 ml of gaseous hydrocarbon on combustion gives 40 ml of CO2(g) and 50 ml ofH2O (vap.). The hydrocarbon is

The correct option is D C4H10 CxHyO2⟶CO2+H2O 10ml 40ml 50ml 1mole 4mole 5mole Apply POAC for C X =4 Apply POAC for H Y=10

10 ml of gaseous hydrocarbon on combustion gives 40 ml of $C O_{2}$ (g) and 50 ml of $H_{2} O$ (vap.). The hydrocarbon is

The correct option is D
C₄H₁₀

$C_{x} H_{y}$ $O_{2}$ $⟶$ $C O_{2}$ + $H_{2} O$

10ml 40ml 50ml

1mole 4mole 5mole

Apply POAC for C

X =4

Apply POAC for H

Y=10