10 times the numerator exceeds 5 times the denominator by 30. The equation satisfying the statement is
Both (a) and (b)
Let the numerator of a fraction be x and denominator be y.
10 times the numerator (10x) exceeds 5 times denominator (5y) by 30
⇒(10x−5y=30)
If we interchange the numerator and denominator as y and x resp then
The equation is 10y–5x=30
∴ Both A and B are correct solutions.