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Question

100 g sample of clay (containing 19% H2O, 40% silica, and inert impurities as rest) is partially dried so as to contain 10% of H2O.
Which of the following is/are correct statement(s)?

A
The percentage of silica in partially dried clay is 44.4%
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B
The mass of partially dried clay is 90 g
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C
The percentage of inert impurity in partially dried clay is 45.6%
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D
The mass of water evaporated is 10 g
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Solution

The correct options are
A The percentage of silica in partially dried clay is 44.4%
B The mass of partially dried clay is 90 g
C The percentage of inert impurity in partially dried clay is 45.6%
D The mass of water evaporated is 10 g
Given, 100 g of the sample,
mass of silica = 40 g
mass of water = 19 g
mass of impurities = 100 -59 = 41 g

After drying, the percentage of water is 10 %. Let a g is the mass of water lost.
19a100a×100=10
a=10 g
Mass of the clay after drying = 100 - 10 = 90 g
percentage of silica = 4090×100=44.4
percentage of impurities = 4190×100=45.6

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