Question

# 100 g sample of clay (containing 19% H2O, 40% silica, and inert impurities as rest) is partially dried so as to contain 10% of H2O. Which of the following is/are correct statement(s)?

A
The percentage of silica in partially dried clay is 44.4%
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B
The mass of partially dried clay is 90 g
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C
The percentage of inert impurity in partially dried clay is 45.6%
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D
The mass of water evaporated is 10 g
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Solution

## The correct options are A The percentage of silica in partially dried clay is 44.4% B The mass of partially dried clay is 90 g C The percentage of inert impurity in partially dried clay is 45.6% D The mass of water evaporated is 10 g Given, 100 g of the sample, mass of silica = 40 g mass of water = 19 g mass of impurities = 100 -59 = 41 g After drying, the percentage of water is 10 %. Let a g is the mass of water lost. ⇒19−a100−a×100=10 a=10 g Mass of the clay after drying = 100 - 10 = 90 g percentage of silica = 4090×100=44.4 percentage of impurities = 4190×100=45.6

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