Question

100 mL of a 0.1 M HCl solution, 200 mL of a 0.2 M HCl solution, 300 mL of a 0.3 M HCl solution, 400 mL of a 0.4 M HCl solution and 500 mL of a 0.5 M HCl solution are mixed. 200 mL of this solution is diluted with 300 mL of water. What is the molarity of HCl in the resultant solution?

A
0.147 M
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B
0.375 M
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C
0.765 M
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D
0.625 M
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Solution

The correct option is A 0.147 MMolarity of the solution when all the given solutions are mixed =(100×0.1)+(200×0.2)+(300×0.3)+(400×0.4)+(500×0.5)1500 = 5501500 M Now, 200 mL of this solution is diluted to 500 mL by adding 300 mL of water. MiVi=MfVf Where Mi is the molarity of the initial solution and Mf is the molarity of the solution after dilution and Vi and Vf are their respective volumes. 5501500×200=Mf×500 Mf=0.147 M

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