1
Question
100 ml of PH3 when decomposed produces phosphorus and hydrogen. The change in volume is:
Open in App
Solution
The correct option is A 50 ml increase
The equation for the decomposition is:
4PH3(g)→P4(s)+6H2(g) (Elemental phosphorus exists as tetra-atomic molecules).
When the temperature and pressure remain the same, 4 ml of PH3 will give 6 ml of H2. (On applying Gay-Lussac's law ).
Hence, 100 ml of PH3 will yield 150 ml of H2.
Increase in volume = (150-100) ml = 50 ml. (The volume of solid phosphorus is negligible).
Hence, the correct option is A
The equation for the decomposition is:
4PH3(g)→P4(s)+6H2(g) (Elemental phosphorus exists as tetra-atomic molecules).
When the temperature and pressure remain the same, 4 ml of PH3 will give 6 ml of H2. (On applying Gay-Lussac's law ).
Hence, 100 ml of PH3 will yield 150 ml of H2.
Increase in volume = (150-100) ml = 50 ml. (The volume of solid phosphorus is negligible).
Hence, the correct option is A
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
