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Question

100 ml of tap water containing $$Ca(HCO_3)_2$$ was titrated with N/50 $$HCl$$ with methyl orange as indicator. If 30ml of $$HCl$$ were required, calculate the temporary hardness as part of $$CaCO_3$$ per $$10^6$$ parts of water.


A
150 ppm
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B
300 ppm
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C
450 ppm
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D
600 ppm
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Solution

The correct option is B 300 ppm
Milli equivalent of $$Ca(HCO_{3})_{2}$$= miili equivalent of $$CaCO_{3}$$= mili equivalent of $$HCl$$
$$N_{1}V_{1}= N_{2}V_{2}$$
$$1000 \times w$$/($$100$$/$$2$$)= $$30$$/$$50$$
$$w$$= $$0.03$$ g
For $$100$$ml the amount of $$CaCO_{3} = 0.03$$ g
For $$10^{6}$$ = $$0.03 \times 10^{6}$$/$$100=300$$ ppm

Chemistry

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