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Question

100mL of 0.15MHCl is mixed with 100mL of 0.005MHCl, what is the pH of resulting solution approximately?

A
2.5
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B
1.5
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C
2
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D
1
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Solution

The correct option is A 2.5
Resultant Molarity = M1V1+M2V2V1+V2
=(0.15)×(100)+(0.005)×100200
=100[0.155]200=0.1552=0.785
pH=log(H+)
=log(0.785)=2.5

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