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Question

100ml of 0.1N NaOH is mixed with 100ml of 0.1NH2SO4. The pH of the resultant solution is :

A
<7
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B
>7
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C
=7
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D
Cannot be predicated
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Solution

The correct option is A <7
equivalent of NaOH=0.1×0.1=0.01
equivalents of H2SO4=0.1×0.1=0.01
moles of H2SO4=0.012=0.005
So 0.05 moles H2SO4 will react with 0.05 mole NaOH and 0.0050.2L=0.025.
PoH=log(OH)=1.60
pH=13.39
SopH>7

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