(111−29)+9 equals
91
149
131
73
We know that (x−y)+z=x−(y−z), for all numbers x, y, z with y>z.
Since the above is true for all the numbers, it must be true for x=111, y=29 and z=9 also, as y=29>9=z
So, (111−29)+9 = 111−(29−9)=111−20=91
Find the range of the following data 92629−1062273424123133023413−95−6−4