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Molar and Specific Heat Capacity

12 mL of 0....

Question

$12 m L$ of $0.25 N$ sulphuric acid is neutralised with $15 m L$ of sodium hydroxide solution on titration. Calculate the normality of the sodium hydroxide solution?

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Solution

$(V * N)_{(} N a O H) = (V * N)_{(} H_{2} S O_{4})$
$N_{N} a O H = \frac{(V * N)_{(} H_{2} S O_{4})}{V_{N} a O H}$
$\frac{12 * 0.25}{15}$
$= 0.2 N$

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