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Mean

12-n, 12, 12+...

Question

$12 - n, 12, 12 + n$
What is the average (arithmetic mean) of the $3$ quantities in the list above?

4

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12

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18

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4 + \frac{n}{3}

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12 + \frac{n}{3}

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Solution

The correct option is E $12$
Given $3$ Quantities: $12$ $-$ $n$ , $12$ , $12$ $+$ $n$

Average of the above $3$ Quantities $=$ $\frac{Sum of the above 3 Quantities}{Number of Quantities}$

$=$ $\frac{12 - n + 12 + 12 + n}{3}$

$=$ $\frac{12 \times 3}{3}$

$=$ $12$

Therefore, average of the Quantities listed above is $12$ .

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