Question

12 positive charges each of magnitude q are placed on a circle of radius R in a manner such that they are equally spaced. A charge +Q is placed at the centre. If one of the charges q is removed, then the force on Q is :

Open in App

Solution

The correct option is **D** qQ4πϵ0R2 towards the position of the removed charge

**Answer is D.**

Q provides the centripetal force required for q to move in a uniform circular motion. The magnitude of the force is given as F=qQ4πε0R2.

Therefore, If one charge is removed then net force on Q is qQ4πε0R2**towards the position of removed charge as it is positive.**

Q provides the centripetal force required for q to move in a uniform circular motion. The magnitude of the force is given as F=qQ4πε0R2.

Therefore, If one charge is removed then net force on Q is qQ4πε0R2

0

View More