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Question

125 mL of 63% (w/v) H2C2O42H2O solution is made to react with 125 mL of a 40%(w/v) NaOH solution. The resulting solution is:

A
neutral
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B
acidic
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C
strongly acidic
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D
alkaline
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Solution

The correct option is C neutral
The resulting solution is neutral in nature because oxalic acid is an acid, sodium hydroxide is a base. and they have the same concentration (Normality).
Normality of oxalic acid is 8N.
Normality of sodium hydroxide is 8N.
So answer is A.

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