Question

$13$ and $31$ is a strange pair of numbers such that their squares 169 and 961 are also mirror images of each other. Find two more such pairs.

Answer 1

(13)2=169 and (31)2=961 (13)^2 = 169 ~ and ~(31)^2 = 961

$(13{)}^2=169$ and $(31{)}^2=961$

Similarly, two such numbers can be $12$ and $21.$

$\therefore (12{)}^2=144,{21}^2=441$

and $102,201$

$(102{)}^2=10404,(201{)}^2=40401$