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Question

1417×1417 can be represented as ___________.


  1. 1417+17


  2. (142)17

  3. All of the above

  4. (14×14)17


Solution

The correct option is C

All of the above


For any positive real number 'a' and integers 'm' and 'n', we define
1. 
am×an=am+n
2. (am)n=amn
3. (ab)m=ambm  and if  a=b, the expression becomes  (a×a)m=(a2)m=a2m.

​​​​​​So, using first rule, we have
1417+17=1427
Now, using second rule,
(142)17= 1427
Finally, using third rule,
(14×14)17 =1427
Hence, we see that all the three results are same.

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