Question

# 1417×1417 can be represented as ___________.1417+17 (142)17 All of the above (14×14)17

Solution

## The correct option is C All of the above For any positive real number 'a' and integers 'm' and 'n', we define 1. am×an=am+n 2. (am)n=amn 3. (ab)m=ambm  and if  a=b, the expression becomes  (a×a)m=(a2)m=a2m. ​​​​​​So, using first rule, we have 1417+17=1427 Now, using second rule, (142)17= 1427 Finally, using third rule, (14×14)17 =1427 Hence, we see that all the three results are same.

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