Question

$1500$J of heat energy is required to raise the temperature of a metallic ball of $300$g from $5^{\circ }C$ to ${15}^{\circ }C$. Calculate the specific heat capacity of the metal ball.

• A. $50J{kg}^{-1}{K}^{-1}$
• B. $0.5J{kg}^{-1}{K}^{-1}$
• C. $0.05J{kg}^{-1}{K}^{-1}$
• D. $500J{kg}^{-1}{K}^{-1}$

Answer 1

Answer: (D)

$500J{kg}^{-1}{K}^{-1}$

Given:
mass $\left(m\right)=300g=0.3kg$
Heat energy required $\left(Q\right)=1500J$
Rise in temperature $\Delta t=15-5={10}^{\circ }C=10K$
Specific heat capacity $=\frac{Heatenergy\left(Q\right)}{Mass\left(m\right)\times Riseintemperature\Delta t}$
= $1500/(0.3\times 10)$
$500J{kg}^{-1}{K}^{-1}$