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Question

16 tuning forks are arranged in the order of increasing frequencies. Any two successive fork give 8 beats per sec when sounded together. If the last fork gives the octave of the first, then the frequency of the first fork is-

A
n = 120
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B
n = 160
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C
n = 180
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D
n = 220
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Solution

The correct option is A n = 120
Let the frequency of the first forks be n. Then the frequencies of the successive forks will be (n+8),(n+16)........+2n. This forms an arithmetic progression. The last term L is 2n the first term A is n and the common differenceis 8
Since,
L=A+(N1)d
2n=n+(161)8
n=120

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