17- Angle A of an isosceles -ABC is acute in which AB - AC- and BD perpendicular to AC- prove that -BC- - 2AC-CD -

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17. Angle A o...

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17. Angle A of an isosceles ΔABC is acute in which AB = AC, and BD perpendicular to AC, prove that (BC) = 2AC.CD ?

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In ΔABC, AB = AC and BD ⊥ AC prove that BD² + CD² = 2AC.CD.

{B C}^{2} = A C \times C D

A B C

A B = A C,

B D

B

A C .

B D^{2} - C D^{2} = 2 C D . A D

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