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Question

18.72 g of a substance 'X' occupies 1.81 $$cm^3$$. What will be its density measured in correct significant figures?


A
10.3 g cm3
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B
10.34 g cm3
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C
10.4 g cm3
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D
10.3425 g cm3
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Solution

The correct option is A 10.3 g $$cm^{-3}$$
Density is mass per unit volume of the substance

$$Density,\ \rho =\dfrac { mass\ (m) }{ Volume\ (V) } $$

Given :$$m=18.72\ g$$ and $$V=1.81\ cm^{3}$$

on substituting we get:

$$\rho =\dfrac { 18.72 }{ 1.81 } =10.3425$$

Rule: Answer to a multiplication or division should be rounded off to the same number of significant figures as possessed by the least precise term in the calculation.
least precise is $$1.81$$ with 3 significant figures thus, the answer will also posses 3 significant figures as $$10.3\ g\ cm^{-3}$$ 

Hence, the correct option is $$A$$

Chemistry

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