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Range of Trigonometric Ratios from 0 to 90 Degrees

18. If tanθ =...

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18. If tanθ =1+ 2tanα , prove that sinθ =(1+ sinα )

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\frac{tan θ + sin θ}{tan θ - sin θ} = \frac{sec θ + 1}{sec θ - 1}

\frac{s e c θ + t a n θ - 1}{t a n θ - s e c θ + 1} = \frac{1 + s i n θ}{c o s θ}

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Range of Trigonometric Ratios from 0 to 90

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Range of Trigonometric Ratios from 0 to 90 Degrees

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