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Summary for Time, Height and Range

18.Path of a ...

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18.Path of a projectile projected from the ground is given as y=ax-bx^2. Find angle of projection, maximum height attained and horizontal range of the projectile.

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Q. Single Correct Answer Type
The path of a projectile is given by the equation

y = a x - b x^{2}

a

b

are constants and

x

y

are respectively horizontal and vertical distances of projectile from the point of projection. The maximum height attained by the projectile and the angle of projection are respectively:

Q. The trajectory of a projectile in a vertical plane is given by

y = a x - b x^{2},

a

b

are constants and

x

y

are respectively horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection from the horizontal are

Q. The trajectory of a projectile in a vertical plane is

y = a x - b x^{2},

a

b

are constants and

x

y

are horizontal and vertical distances respectively of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection from the horizontal are:

Q. The trajectory of a projectile in a vertical plane is

y = a x - b x^{2}

a

b

are constants and

x

y

are, respectively, horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection from the horizontal are

Q. The trajectory of a projectile in a vertical plane is

y = a x - {b x}^{2}

a

b

are constants, and

x

y

are, respectively, the horizontal and vertical distance of the projectile from the point of projection. The maximum height attained is ________ and the angle of projectile from the horizontal is _______.

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Summary for Time, Height and Range

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