19.The electric field in a certain region of space points in the z direction and a magnitude is equals to E=5xz where x in z are measured from some origin calculate the flux of the field through a square perpendicular to the z axis the corners of the square are at (-1,-1,1) (-1,2,1) (2,2,1) and (2,-1,1)

Open in App

Solution

Suggest Corrections

Similar questions

Q. A uniform electric field of magnitude

E = 100 N/C

exists in the space in

+ x -

direction. Calculate the flux of this field through a plane square of edge

10 cm

placed in the

y - z

plane. Take the normal along the positive

x -

axis to be positive.

Q. Point charges each of magnitude

Q

are placed at three corners of a square as shown in the diagram.
What is the direction of the resultant electric field at the fourth corner?

Q. Four point charges +q, +q, -q and -q are placed on the corners of a square of side length

^{'} a^{'}

as shown in the figure. Magnitude of electric field at a point which is at a distance

x

(>>

a

) from the centre along a line perpendicular to the plane of square and passing through the center is

Q. Three point charges of

3 \times 10^{- 9} C

are situated at each of three corners of a square, whose side is

15 c m

. The magnitude and direction of the electric field at the vacant corner of the square are:

Point charges of $3 \times 10^{- 9} C$ are situated at each of the three corners of a square whose side is $15 c m$ . The magnitude and direction of electric field at the vacant corner of the square is :

Join BYJU'S Learning Program

Select...