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Question

1mole of propane on combustion at stp gives A kilojoules of heat energy . Calculate the heat liberated when 2.4litres of propane on combustion at STP

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Solution

1 mole at s.t.p is 22.4 litrea
so, if 1 mole =22.4 litres
therefore ? = 2.4litres

2.4 x 1/22.4 = 0.1071428 moles

if one mole of propane = 1KJ
therefore 0.1071428 moles = ?

0.1071428 x1/1

therefore 2.4 litres is 0.1071428 KJ

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